(1/125)^2x+1=(1/5)^3x-3

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Solution for (1/125)^2x+1=(1/5)^3x-3 equation: 



(1/125)^2x+1=(1/5)^3x-3

We move all terms to the left:

(1/125)^2x+1-((1/5)^3x-3)=0



Domain of the equation: 125)^2x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5)^3x-3)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+1/125)^2x-((+1/5)^3x-3)+1=0

We calculate fractions


5^3x/125^2x*5)^3x-3))+(-125^2x/125^2x*5)^3x-3))+1=0

We can not solve this equation

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